To solve the equation 8^x + 2^x = 130, we can first factor out a 2^x from both sides:
2^x(8 + 1) = 130
2^x * 9 = 130
Then, we can divide both sides by 9 to isolate x:
2^x = 130/9
To find the value of x, we can take the logarithm of both sides of the equation. The logarithm base 2 of 130/9 is approximately 2.32192809. Therefore, x is approximately equal to 2.32192809.
Another way to solve the equation is to use a graphing calculator. We can graph the functions 8^x and 2^x and find the point where they intersect. The point of intersection is approximately (2.32192809, 130). Therefore, x is approximately equal to 2.32192809.
Therefore, the solution to the equation 8^x + 2^x = 130 is x = approximately 2.32192809.
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(2^x -5)(2^2x+5×2^x+26)=0;
2^x=5; x=log2(5);
x=2,32
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