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المساحة المطلوبة=

cos(30)=x/2R=(2R+1)/(2√3+x) , x=R√3 R^2+2R=6R>R=4units S(green)=(1/2*Π*16)-[(1/2)*(Π/3)*16+(1/2)*16*√3/2] S(green)=8Π-(8Π/3+4√3) =(16Π/3-4√3)units^2

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√3r(√3r+2√3)=2r(2r+1)

3r+6=4r+2

r=4

المساحة المطلوبة=

1/2×16(2π/3-√3/2)=16π/3-4√3

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