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2023-11-02T19:50:00+02:00
x2 = 4 ↔ x2 - 4=0(x-2)(x+2)=0 then x =+2 or-2 y2 = 6 — y2 — 6 =0 → (x−√6)(x+√6) = 0 then y =±√6 if x = 2 and y = √6 = then (2)1 +3( √ √/6...
Read more »x2 = 4 ↔ x2 - 4=0(x-2)(x+2)=0 then x =+2 or-2 y2 = 6 — y2 — 6 =0 → (x−√6)(x+√6) = 0 then y =±√6 if x = 2 and y = √6 = then (2)1 +3( √ √/6...
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