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جد طول الوتر
S1 + S2 = 6000
S = 6000
(2x+60).(x+40) = 6000
2.(x+30)(x+40) = 6000
(x+30).(x+40) = 3000
x² + 40x +30x + 1200 = 3000
x² + 70x -1800 = 0
x² -20x +90x -1800 = 0
x.( x -20) -90(x - 20) = 0
(x - 20).(x - 90) = 0
x1= 20 and x2 = 90
For x = 20 x+40 = 20+40 = 60
x + 60 = 20 + 60 = 80
C² = 60² + 80² = 10000 <=> c = 100
For x = 90 x+40 = 130
x +60 = 150
c² = 17200 <=> c ≈ 113.15.
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